What are the solutions to the equation (x(x-3))/2 =28 ?

The solutions to the equation (x(x-3))/2 =28 are x=(3+sqrt(233))/2 ,x=(3-sqrt(233))/2

Find the zeros of (x(x-3))/2 =28

The zeros of (x(x-3))/2 =28 are x=(3+sqrt(233))/2 ,x=(3-sqrt(233))/2

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\frac{x ( x - 3 )}{2} = 28

x = \frac{3 + 233}{2}, x = \frac{3 - 233}{2}

Decimal Notation

x = 9.13216 \dots, x = - 6.13216 \dots

Solution steps

\frac{x ( x - 3 )}{2} = 28

Multiply both sides by

2

x (x - 3) = 56

Expand

x (x - 3) : x^{2} - 3 x

x^{2} - 3 x = 56

Move

56

to the left side

x^{2} - 3 x - 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 56 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 56) = 233

x_{1, 2} = \frac{- ( - 3 ) \pm 233}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 233}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 233}{2 \cdot 1}

x = \frac{- ( - 3 ) + 233}{2 \cdot 1} : \frac{3 + 233}{2}

x = \frac{- ( - 3 ) - 233}{2 \cdot 1} : \frac{3 - 233}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 233}{2}, x = \frac{3 - 233}{2}

0.02 a^{2} - 0.02 a - 0.01 = 0

(3 x - 4) (x + 2) = 8

3 t^{2} - 3 t - 5 = 0

(x - 9) (x + 5) = - 13

x, x^{2} - y x + 64 = 0

What are the solutions to the equation (x(x-3))/2 =28 ?
The solutions to the equation (x(x-3))/2 =28 are x=(3+sqrt(233))/2 ,x=(3-sqrt(233))/2
Find the zeros of (x(x-3))/2 =28
The zeros of (x(x-3))/2 =28 are x=(3+sqrt(233))/2 ,x=(3-sqrt(233))/2