What are the solutions to the equation 3t^2-3t-5=0 ?

The solutions to the equation 3t^2-3t-5=0 are t=(3+sqrt(69))/6 ,t=(3-sqrt(69))/6

Find the zeros of 3t^2-3t-5=0

The zeros of 3t^2-3t-5=0 are t=(3+sqrt(69))/6 ,t=(3-sqrt(69))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 t^{2} - 3 t - 5 = 0

t = \frac{3 + 69}{6}, t = \frac{3 - 69}{6}

Decimal Notation

t = 1.88443 \dots, t = - 0.88443 \dots

Solution steps

3 t^{2} - 3 t - 5 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

(- 3)^{2} - 4 \cdot 3 (- 5) = 69

t_{1, 2} = \frac{- ( - 3 ) \pm 69}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 3 ) + 69}{2 \cdot 3}, t_{2} = \frac{- ( - 3 ) - 69}{2 \cdot 3}

t = \frac{- ( - 3 ) + 69}{2 \cdot 3} : \frac{3 + 69}{6}

t = \frac{- ( - 3 ) - 69}{2 \cdot 3} : \frac{3 - 69}{6}

The solutions to the quadratic equation are:

t = \frac{3 + 69}{6}, t = \frac{3 - 69}{6}

(x - 9) (x + 5) = - 13

x, x^{2} - y x + 64 = 0

(x + 10)^{2} = 36

(- 4 x - 3) (x - 3) = 0

(x + 13)^{2} = - 36

What are the solutions to the equation 3t^2-3t-5=0 ?
The solutions to the equation 3t^2-3t-5=0 are t=(3+sqrt(69))/6 ,t=(3-sqrt(69))/6
Find the zeros of 3t^2-3t-5=0
The zeros of 3t^2-3t-5=0 are t=(3+sqrt(69))/6 ,t=(3-sqrt(69))/6