What are the solutions to the equation (-4x-3)(x-3)=0 ?

The solutions to the equation (-4x-3)(x-3)=0 are x=-3/4 ,x=3

Find the zeros of (-4x-3)(x-3)=0

The zeros of (-4x-3)(x-3)=0 are x=-3/4 ,x=3

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(- 4 x - 3) (x - 3) = 0

x = - \frac{3}{4}, x = 3

Decimal Notation

x = - 0.75, x = 3

Solution steps

(- 4 x - 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

- 4 x - 3 = 0 or x - 3 = 0

Solve

- 4 x - 3 = 0 : x = - \frac{3}{4}

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = - \frac{3}{4}, x = 3

(x + 13)^{2} = - 36

4 x^{2} + 6 = 3 x^{2} + 18

(5 x - 2)^{2} = (2 x - 5)^{2}

- x^{2} + 13 x - 42 = 0

x^{2} - 3 x - \frac{7}{4} = 0

What are the solutions to the equation (-4x-3)(x-3)=0 ?
The solutions to the equation (-4x-3)(x-3)=0 are x=-3/4 ,x=3
Find the zeros of (-4x-3)(x-3)=0
The zeros of (-4x-3)(x-3)=0 are x=-3/4 ,x=3