What are the solutions to the equation 4x^2+6=3x^2+18 ?

The solutions to the equation 4x^2+6=3x^2+18 are x=2sqrt(3),x=-2sqrt(3)

Find the zeros of 4x^2+6=3x^2+18

The zeros of 4x^2+6=3x^2+18 are x=2sqrt(3),x=-2sqrt(3)

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4 x^{2} + 6 = 3 x^{2} + 18

x = 23, x = - 23

Decimal Notation

x = 3.46410 \dots, x = - 3.46410 \dots

Solution steps

4 x^{2} + 6 = 3 x^{2} + 18

Move

6

to the right side

4 x^{2} = 3 x^{2} + 12

Move

3 x^{2}

to the left side

x^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 12, x = - 12

12 = 23

- 12 = - 23

x = 23, x = - 23

(5 x - 2)^{2} = (2 x - 5)^{2}

- x^{2} + 13 x - 42 = 0

x^{2} - 3 x - \frac{7}{4} = 0

(2 x + 1) 3 x + 6 x (2 x + 1) = - 9 x (1 + 2 x)

x, (C - x) (1 + k x) = B (k q x)

What are the solutions to the equation 4x^2+6=3x^2+18 ?
The solutions to the equation 4x^2+6=3x^2+18 are x=2sqrt(3),x=-2sqrt(3)
Find the zeros of 4x^2+6=3x^2+18
The zeros of 4x^2+6=3x^2+18 are x=2sqrt(3),x=-2sqrt(3)