What are the solutions to the equation x^2-3x-7/4 =0 ?

The solutions to the equation x^2-3x-7/4 =0 are x= 7/2 ,x=-1/2

Find the zeros of x^2-3x-7/4 =0

The zeros of x^2-3x-7/4 =0 are x= 7/2 ,x=-1/2

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x^{2} - 3 x - \frac{7}{4} = 0

x = \frac{7}{2}, x = - \frac{1}{2}

Decimal Notation

x = 3.5, x = - 0.5

Solution steps

x^{2} - 3 x - \frac{7}{4} = 0

Multiply both sides by

4

4 x^{2} - 12 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 (- 7) = 16

x_{1, 2} = \frac{- ( - 12 ) \pm 16}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 16}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 16}{2 \cdot 4}

x = \frac{- ( - 12 ) + 16}{2 \cdot 4} : \frac{7}{2}

x = \frac{- ( - 12 ) - 16}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - \frac{1}{2}

(2 x + 1) 3 x + 6 x (2 x + 1) = - 9 x (1 + 2 x)

x, (C - x) (1 + k x) = B (k q x)

10 x^{2} + 7 x - 5 = 0

0 = - 2 x^{2} - 16 x - 30

4 x^{2} + 30 x - 54 = 0

What are the solutions to the equation x^2-3x-7/4 =0 ?
The solutions to the equation x^2-3x-7/4 =0 are x= 7/2 ,x=-1/2
Find the zeros of x^2-3x-7/4 =0
The zeros of x^2-3x-7/4 =0 are x= 7/2 ,x=-1/2