What are the solutions to the equation solvefor x,x^2=2y+4z ?

The solutions to the equation solvefor x,x^2=2y+4z are x=sqrt(2y+4z),x=-sqrt(2y+4z)

Find the zeros of solvefor x,x^2=2y+4z

The zeros of solvefor x,x^2=2y+4z are x=sqrt(2y+4z),x=-sqrt(2y+4z)

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solve for

x, x^{2} = 2 y + 4 z

x = 2 y + 4 z, x = - 2 y + 4 z

Solution steps

x^{2} = 2 y + 4 z

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2 y + 4 z, x = - 2 y + 4 z

x^{2} - 18 x + 74 = 0

7 (2 x^{2} - 1) = 5 x

3 x^{2} - x = 14

n^{2} = 625

7 y^{2} - 35 y = 0

What are the solutions to the equation solvefor x,x^2=2y+4z ?
The solutions to the equation solvefor x,x^2=2y+4z are x=sqrt(2y+4z),x=-sqrt(2y+4z)
Find the zeros of solvefor x,x^2=2y+4z
The zeros of solvefor x,x^2=2y+4z are x=sqrt(2y+4z),x=-sqrt(2y+4z)