What are the solutions to the equation 3x^2-x=14 ?

The solutions to the equation 3x^2-x=14 are x= 7/3 ,x=-2

Find the zeros of 3x^2-x=14

The zeros of 3x^2-x=14 are x= 7/3 ,x=-2

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3 x^{2} - x = 14

x = \frac{7}{3}, x = - 2

Decimal Notation

x = 2.33333 \dots, x = - 2

Solution steps

3 x^{2} - x = 14

Move

14

to the left side

3 x^{2} - x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 14 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 14) = 13

x_{1, 2} = \frac{- ( - 1 ) \pm 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 13}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 13}{2 \cdot 3}

x = \frac{- ( - 1 ) + 13}{2 \cdot 3} : \frac{7}{3}

x = \frac{- ( - 1 ) - 13}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = - 2

n^{2} = 625

7 y^{2} - 35 y = 0

18 t + 2 t^{2} - 180 = 0

n^{2} = 6 + n

3 (x + 4)^{2} = 25

What are the solutions to the equation 3x^2-x=14 ?
The solutions to the equation 3x^2-x=14 are x= 7/3 ,x=-2
Find the zeros of 3x^2-x=14
The zeros of 3x^2-x=14 are x= 7/3 ,x=-2