What are the solutions to the equation 3(x+4)^2=25 ?

The solutions to the equation 3(x+4)^2=25 are x= 5/(sqrt(3))-4,x=-5/(sqrt(3))-4

Find the zeros of 3(x+4)^2=25

The zeros of 3(x+4)^2=25 are x= 5/(sqrt(3))-4,x=-5/(sqrt(3))-4

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3 (x + 4)^{2} = 25

x = \frac{5}{3} - 4, x = - \frac{5}{3} - 4

Decimal Notation

x = - 1.11324 \dots, x = - 6.88675 \dots

Solution steps

3 (x + 4)^{2} = 25

Divide both sides by

3

(x + 4)^{2} = \frac{25}{3}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = \frac{25}{3} : x = \frac{5}{3} - 4

Solve

x + 4 = - \frac{25}{3} : x = - \frac{5}{3} - 4

The solutions to the quadratic equation are:

x = \frac{5}{3} - 4, x = - \frac{5}{3} - 4

x^{2} + (2 x + 1)^{2} = 10

5 n^{2} = 6 n - 1

- 3 = g^{2} - 4 g

- x^{2} + 2 x = - 1

2 y^{2} = 16

What are the solutions to the equation 3(x+4)^2=25 ?
The solutions to the equation 3(x+4)^2=25 are x= 5/(sqrt(3))-4,x=-5/(sqrt(3))-4
Find the zeros of 3(x+4)^2=25
The zeros of 3(x+4)^2=25 are x= 5/(sqrt(3))-4,x=-5/(sqrt(3))-4