What are the solutions to the equation -3=g^2-4g ?

The solutions to the equation -3=g^2-4g are g=3,g=1

Find the zeros of -3=g^2-4g

The zeros of -3=g^2-4g are g=3,g=1

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- 3 = g^{2} - 4 g

g = 3, g = 1

Solution steps

- 3 = g^{2} - 4 g

Switch sides

g^{2} - 4 g = - 3

Move

3

to the left side

g^{2} - 4 g + 3 = 0

Solve with the quadratic formula

g_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 3 = 2

g_{1, 2} = \frac{- ( - 4 ) \pm 2}{2 \cdot 1}

Separate the solutions

g_{1} = \frac{- ( - 4 ) + 2}{2 \cdot 1}, g_{2} = \frac{- ( - 4 ) - 2}{2 \cdot 1}

g = \frac{- ( - 4 ) + 2}{2 \cdot 1} : 3

g = \frac{- ( - 4 ) - 2}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

g = 3, g = 1

- x^{2} + 2 x = - 1

2 y^{2} = 16

2 y^{2} = 54

x, x^{2} + 5 x = - y + 6 a

c^{2} - 15 c + 54 = 0

What are the solutions to the equation -3=g^2-4g ?
The solutions to the equation -3=g^2-4g are g=3,g=1
Find the zeros of -3=g^2-4g
The zeros of -3=g^2-4g are g=3,g=1