What are the solutions to the equation (2x-7)^2=81 ?

The solutions to the equation (2x-7)^2=81 are x=8,x=-1

Find the zeros of (2x-7)^2=81

The zeros of (2x-7)^2=81 are x=8,x=-1

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(2 x - 7)^{2} = 81

x = 8, x = - 1

Solution steps

(2 x - 7)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 7 = 81 : x = 8

Solve

2 x - 7 = - 81 : x = - 1

The solutions to the quadratic equation are:

x = 8, x = - 1

0 = 5 x^{2} + 29 x - 6

6 x^{2} - 49 = 0

x^{2} = - 17 x

x^{2} = - 175

x^{2} - 180 x + 20000 = 0

What are the solutions to the equation (2x-7)^2=81 ?
The solutions to the equation (2x-7)^2=81 are x=8,x=-1
Find the zeros of (2x-7)^2=81
The zeros of (2x-7)^2=81 are x=8,x=-1