What are the solutions to the equation (x+4)^2-16(x+4)+63=0 ?

The solutions to the equation (x+4)^2-16(x+4)+63=0 are x=5,x=3

Find the zeros of (x+4)^2-16(x+4)+63=0

The zeros of (x+4)^2-16(x+4)+63=0 are x=5,x=3

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(x + 4)^{2} - 16 (x + 4) + 63 = 0

x = 5, x = 3

Solution steps

(x + 4)^{2} - 16 (x + 4) + 63 = 0

Expand

(x + 4)^{2} - 16 (x + 4) + 63 : x^{2} - 8 x + 15

x^{2} - 8 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

x_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

x = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 5, x = 3

c^{2} = (6)^{2} + x^{2}

x, f (x + 2) = 3 x^{2} + 4

x, f (x + 2) = 3 x^{2} + 5

2 x (x - 2) = 8 x^{2} - 5 x

x, 1 - 1.4 x + 0.6 x^{2} = 0

What are the solutions to the equation (x+4)^2-16(x+4)+63=0 ?
The solutions to the equation (x+4)^2-16(x+4)+63=0 are x=5,x=3
Find the zeros of (x+4)^2-16(x+4)+63=0
The zeros of (x+4)^2-16(x+4)+63=0 are x=5,x=3