What are the solutions to the equation 2x(x-2)=8x^2-5x ?

The solutions to the equation 2x(x-2)=8x^2-5x are x=0,x= 1/6

Find the zeros of 2x(x-2)=8x^2-5x

The zeros of 2x(x-2)=8x^2-5x are x=0,x= 1/6

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2 x (x - 2) = 8 x^{2} - 5 x

x = 0, x = \frac{1}{6}

Decimal Notation

x = 0, x = 0.16666 \dots

Solution steps

2 x (x - 2) = 8 x^{2} - 5 x

Expand

2 x (x - 2) : 2 x^{2} - 4 x

2 x^{2} - 4 x = 8 x^{2} - 5 x

Move

5 x

to the left side

2 x^{2} + x = 8 x^{2}

Move

8 x^{2}

to the left side

- 6 x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 6 ) \cdot 0}{2 ( - 6 )}

1^{2} - 4 (- 6) \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 ( - 6 )}, x_{2} = \frac{- 1 - 1}{2 ( - 6 )}

x = \frac{- 1 + 1}{2 ( - 6 )} : 0

x = \frac{- 1 - 1}{2 ( - 6 )} : \frac{1}{6}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{6}

x, 1 - 1.4 x + 0.6 x^{2} = 0

x, 4 x^{2} = (y - x)^{2}

2 x^{2} - 7 = - 169

0.02 x^{2} - 0.3 x - 20 = 0

x^{2} - 6 x = 8

What are the solutions to the equation 2x(x-2)=8x^2-5x ?
The solutions to the equation 2x(x-2)=8x^2-5x are x=0,x= 1/6
Find the zeros of 2x(x-2)=8x^2-5x
The zeros of 2x(x-2)=8x^2-5x are x=0,x= 1/6