What are the solutions to the equation 2x^2-7=-169 ?

The solutions to the equation 2x^2-7=-169 are x=9i,x=-9i

Find the zeros of 2x^2-7=-169

The zeros of 2x^2-7=-169 are x=9i,x=-9i

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2 x^{2} - 7 = - 169

x = 9 i, x = - 9 i

Solution steps

2 x^{2} - 7 = - 169

Move

7

to the right side

2 x^{2} = - 162

Divide both sides by

2

x^{2} = - 81

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 81, x = - - 81

- 81 = 9 i

- - 81 = - 9 i

x = 9 i, x = - 9 i

0.02 x^{2} - 0.3 x - 20 = 0

x^{2} - 6 x = 8

3.4 \cdot 1 0^{- 6} = x (0.5 + x)

4 x^{2} + 16 x + 8 = 0

(3 x + 1) (2 x - 5) = 0

What are the solutions to the equation 2x^2-7=-169 ?
The solutions to the equation 2x^2-7=-169 are x=9i,x=-9i
Find the zeros of 2x^2-7=-169
The zeros of 2x^2-7=-169 are x=9i,x=-9i