What are the solutions to the equation 0.02x^2-0.3x-20=0 ?

The solutions to the equation 0.02x^2-0.3x-20=0 are x=40,x=-25

Find the zeros of 0.02x^2-0.3x-20=0

The zeros of 0.02x^2-0.3x-20=0 are x=40,x=-25

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0.02 x^{2} - 0.3 x - 20 = 0

x = 40, x = - 25

Solution steps

0.02 x^{2} - 0.3 x - 20 = 0

Multiply both sides by

100

2 x^{2} - 30 x - 2000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 2 ( - 2000 )}{2 \cdot 2}

(- 30)^{2} - 4 \cdot 2 (- 2000) = 130

x_{1, 2} = \frac{- ( - 30 ) \pm 130}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 30 ) + 130}{2 \cdot 2}, x_{2} = \frac{- ( - 30 ) - 130}{2 \cdot 2}

x = \frac{- ( - 30 ) + 130}{2 \cdot 2} : 40

x = \frac{- ( - 30 ) - 130}{2 \cdot 2} : - 25

The solutions to the quadratic equation are:

x = 40, x = - 25

x^{2} - 6 x = 8

3.4 \cdot 1 0^{- 6} = x (0.5 + x)

4 x^{2} + 16 x + 8 = 0

(3 x + 1) (2 x - 5) = 0

25 x^{2} - 9 x = 0

What are the solutions to the equation 0.02x^2-0.3x-20=0 ?
The solutions to the equation 0.02x^2-0.3x-20=0 are x=40,x=-25
Find the zeros of 0.02x^2-0.3x-20=0
The zeros of 0.02x^2-0.3x-20=0 are x=40,x=-25