What are the solutions to the equation 25x^2-9x=0 ?

The solutions to the equation 25x^2-9x=0 are x= 9/25 ,x=0

Find the zeros of 25x^2-9x=0

The zeros of 25x^2-9x=0 are x= 9/25 ,x=0

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25 x^{2} - 9 x = 0

x = \frac{9}{25}, x = 0

Decimal Notation

x = 0.36, x = 0

Solution steps

25 x^{2} - 9 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 25 \cdot 0}{2 \cdot 25}

(- 9)^{2} - 4 \cdot 25 \cdot 0 = 9

x_{1, 2} = \frac{- ( - 9 ) \pm 9}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 9}{2 \cdot 25}, x_{2} = \frac{- ( - 9 ) - 9}{2 \cdot 25}

x = \frac{- ( - 9 ) + 9}{2 \cdot 25} : \frac{9}{25}

x = \frac{- ( - 9 ) - 9}{2 \cdot 25} : 0

The solutions to the quadratic equation are:

x = \frac{9}{25}, x = 0

x^{2} = - 361

0 = - 0.06 x^{2} + 1.31 x + 1.38

5 x^{2} - 20 x - 5

600 x + 400 x (x + 200) = 1700000

1 x^{2} + 4 x + 5 = 0

What are the solutions to the equation 25x^2-9x=0 ?
The solutions to the equation 25x^2-9x=0 are x= 9/25 ,x=0
Find the zeros of 25x^2-9x=0
The zeros of 25x^2-9x=0 are x= 9/25 ,x=0