What are the solutions to the equation 1x^2+4x+5=0 ?

The solutions to the equation 1x^2+4x+5=0 are x=-2+i,x=-2-i

Find the zeros of 1x^2+4x+5=0

The zeros of 1x^2+4x+5=0 are x=-2+i,x=-2-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1 x^{2} + 4 x + 5 = 0

x = - 2 + i, x = - 2 - i

Solution steps

1 \cdot x^{2} + 4 x + 5 = 0

Refine

x^{2} + 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 5 : 2 i

x_{1, 2} = \frac{- 4 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 i}{2 \cdot 1}

x = \frac{- 4 + 2 i}{2 \cdot 1} : - 2 + i

x = \frac{- 4 - 2 i}{2 \cdot 1} : - 2 - i

The solutions to the quadratic equation are:

x = - 2 + i, x = - 2 - i

4 x^{2} - 48 x + 128 = 0

x^{2} + 2 x - 99 = 0

t^{2} - 2 t + 8 = 0

- 31 = 2 - 3 a^{2}

x, 3 x^{2} - 2 x + 2 = 0

What are the solutions to the equation 1x^2+4x+5=0 ?
The solutions to the equation 1x^2+4x+5=0 are x=-2+i,x=-2-i
Find the zeros of 1x^2+4x+5=0
The zeros of 1x^2+4x+5=0 are x=-2+i,x=-2-i