What are the solutions to the equation 4x^2-21x+21=0 ?

The solutions to the equation 4x^2-21x+21=0 are x=(21+sqrt(105))/8 ,x=(21-sqrt(105))/8

Find the zeros of 4x^2-21x+21=0

The zeros of 4x^2-21x+21=0 are x=(21+sqrt(105))/8 ,x=(21-sqrt(105))/8

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4 x^{2} - 21 x + 21 = 0

x = \frac{21 + 105}{8}, x = \frac{21 - 105}{8}

Decimal Notation

x = 3.90586 \dots, x = 1.34413 \dots

Solution steps

4 x^{2} - 21 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 4 \cdot 21}{2 \cdot 4}

(- 21)^{2} - 4 \cdot 4 \cdot 21 = 105

x_{1, 2} = \frac{- ( - 21 ) \pm 105}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 21 ) + 105}{2 \cdot 4}, x_{2} = \frac{- ( - 21 ) - 105}{2 \cdot 4}

x = \frac{- ( - 21 ) + 105}{2 \cdot 4} : \frac{21 + 105}{8}

x = \frac{- ( - 21 ) - 105}{2 \cdot 4} : \frac{21 - 105}{8}

The solutions to the quadratic equation are:

x = \frac{21 + 105}{8}, x = \frac{21 - 105}{8}

a (x) = x^{2} + 7 x - 8

6 x^{2} - 7 x + 2 = 0

- 2 x^{2} = 20 x + 100

50000 = - 17 x^{2} + 2040 x + 121

c^{2} = 4 0^{2} + 9^{2}

What are the solutions to the equation 4x^2-21x+21=0 ?
The solutions to the equation 4x^2-21x+21=0 are x=(21+sqrt(105))/8 ,x=(21-sqrt(105))/8
Find the zeros of 4x^2-21x+21=0
The zeros of 4x^2-21x+21=0 are x=(21+sqrt(105))/8 ,x=(21-sqrt(105))/8