What are the solutions to the equation -2x^2=20x+100 ?

The solutions to the equation -2x^2=20x+100 are x=-5-5i,x=-5+5i

Find the zeros of -2x^2=20x+100

The zeros of -2x^2=20x+100 are x=-5-5i,x=-5+5i

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- 2 x^{2} = 20 x + 100

x = - 5 - 5 i, x = - 5 + 5 i

Solution steps

- 2 x^{2} = 20 x + 100

Move

100

to the left side

- 2 x^{2} - 100 = 20 x

Move

20 x

to the left side

- 2 x^{2} - 100 - 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} - 20 x - 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 ( - 2 ) ( - 100 )}{2 ( - 2 )}

Simplify

(- 20)^{2} - 4 (- 2) (- 100) : 20 i

x_{1, 2} = \frac{- ( - 20 ) \pm 20 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 20 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 20 ) - 20 i}{2 ( - 2 )}

x = \frac{- ( - 20 ) + 20 i}{2 ( - 2 )} : - 5 - 5 i

x = \frac{- ( - 20 ) - 20 i}{2 ( - 2 )} : - 5 + 5 i

The solutions to the quadratic equation are:

x = - 5 - 5 i, x = - 5 + 5 i

50000 = - 17 x^{2} + 2040 x + 121

c^{2} = 4 0^{2} + 9^{2}

d, V = 5 d^{2}

23 u^{2} + 40 u = 0

x^{2} - 6 x + 4 = 0

What are the solutions to the equation -2x^2=20x+100 ?
The solutions to the equation -2x^2=20x+100 are x=-5-5i,x=-5+5i
Find the zeros of -2x^2=20x+100
The zeros of -2x^2=20x+100 are x=-5-5i,x=-5+5i