What are the solutions to the equation x^2-300x-22500=0 ?

The solutions to the equation x^2-300x-22500=0 are x=150(1+sqrt(2)),x=150(1-sqrt(2))

Find the zeros of x^2-300x-22500=0

The zeros of x^2-300x-22500=0 are x=150(1+sqrt(2)),x=150(1-sqrt(2))

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x^{2} - 300 x - 22500 = 0

x = 150 (1 + 2), x = 150 (1 - 2)

Decimal Notation

x = 362.13203 \dots, x = - 62.13203 \dots

Solution steps

x^{2} - 300 x - 22500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 300 ) \pm ( - 300 ) ^{2} - 4 \cdot 1 \cdot ( - 22500 )}{2 \cdot 1}

(- 300)^{2} - 4 \cdot 1 \cdot (- 22500) = 3002

x_{1, 2} = \frac{- ( - 300 ) \pm 300 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 300 ) + 300 2}{2 \cdot 1}, x_{2} = \frac{- ( - 300 ) - 300 2}{2 \cdot 1}

x = \frac{- ( - 300 ) + 300 2}{2 \cdot 1} : 150 (1 + 2)

x = \frac{- ( - 300 ) - 300 2}{2 \cdot 1} : 150 (1 - 2)

The solutions to the quadratic equation are:

x = 150 (1 + 2), x = 150 (1 - 2)

6 x^{2} - 8 x - 7 = 0

y = x^{2} - 5 x + 6, x

x, f (x + 5) = x^{2} + 2 x + 3

(2 x - 1) (2 x + 1) = (2 x - 3) 2

x, f^{1} (x) = x^{2} + 2

What are the solutions to the equation x^2-300x-22500=0 ?
The solutions to the equation x^2-300x-22500=0 are x=150(1+sqrt(2)),x=150(1-sqrt(2))
Find the zeros of x^2-300x-22500=0
The zeros of x^2-300x-22500=0 are x=150(1+sqrt(2)),x=150(1-sqrt(2))