What are the solutions to the equation 6x^2-8x-7=0 ?

The solutions to the equation 6x^2-8x-7=0 are x=(4+sqrt(58))/6 ,x=(4-sqrt(58))/6

Find the zeros of 6x^2-8x-7=0

The zeros of 6x^2-8x-7=0 are x=(4+sqrt(58))/6 ,x=(4-sqrt(58))/6

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6 x^{2} - 8 x - 7 = 0

x = \frac{4 + 58}{6}, x = \frac{4 - 58}{6}

Decimal Notation

x = 1.93596 \dots, x = - 0.60262 \dots

Solution steps

6 x^{2} - 8 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 6 ( - 7 )}{2 \cdot 6}

(- 8)^{2} - 4 \cdot 6 (- 7) = 258

x_{1, 2} = \frac{- ( - 8 ) \pm 2 58}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 58}{2 \cdot 6}, x_{2} = \frac{- ( - 8 ) - 2 58}{2 \cdot 6}

x = \frac{- ( - 8 ) + 2 58}{2 \cdot 6} : \frac{4 + 58}{6}

x = \frac{- ( - 8 ) - 2 58}{2 \cdot 6} : \frac{4 - 58}{6}

The solutions to the quadratic equation are:

x = \frac{4 + 58}{6}, x = \frac{4 - 58}{6}

y = x^{2} - 5 x + 6, x

x, f (x + 5) = x^{2} + 2 x + 3

(2 x - 1) (2 x + 1) = (2 x - 3) 2

x, f^{1} (x) = x^{2} + 2

2 y (y + 5) - 5 = 0

What are the solutions to the equation 6x^2-8x-7=0 ?
The solutions to the equation 6x^2-8x-7=0 are x=(4+sqrt(58))/6 ,x=(4-sqrt(58))/6
Find the zeros of 6x^2-8x-7=0
The zeros of 6x^2-8x-7=0 are x=(4+sqrt(58))/6 ,x=(4-sqrt(58))/6