What are the solutions to the equation y^2+10y+35=0 ?

The solutions to the equation y^2+10y+35=0 are y=-5+sqrt(10)i,y=-5-sqrt(10)i

Find the zeros of y^2+10y+35=0

The zeros of y^2+10y+35=0 are y=-5+sqrt(10)i,y=-5-sqrt(10)i

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y^{2} + 10 y + 35 = 0

y = - 5 + 10 i, y = - 5 - 10 i

Solution steps

y^{2} + 10 y + 35 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

Simplify

1 0^{2} - 4 \cdot 1 \cdot 35 : 210 i

y_{1, 2} = \frac{- 10 \pm 2 10 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 10 + 2 10 i}{2 \cdot 1}, y_{2} = \frac{- 10 - 2 10 i}{2 \cdot 1}

y = \frac{- 10 + 2 10 i}{2 \cdot 1} : - 5 + 10 i

y = \frac{- 10 - 2 10 i}{2 \cdot 1} : - 5 - 10 i

The solutions to the quadratic equation are:

y = - 5 + 10 i, y = - 5 - 10 i

6 x^{2} = 4 - 8 x

x, x^{2} - x = 12

2 ab x^{2} - (b^{2} + 6 a^{2}) x + 3 ab = 0

0 = - 4.9 t^{2} + 100 t + 20

- 1.86 x^{2} + 18.76 x + 1.21 = 10

What are the solutions to the equation y^2+10y+35=0 ?
The solutions to the equation y^2+10y+35=0 are y=-5+sqrt(10)i,y=-5-sqrt(10)i
Find the zeros of y^2+10y+35=0
The zeros of y^2+10y+35=0 are y=-5+sqrt(10)i,y=-5-sqrt(10)i