What are the solutions to the equation 6x^2=4-8x ?

The solutions to the equation 6x^2=4-8x are x=(-2+sqrt(10))/3 ,x=-(2+sqrt(10))/3

Find the zeros of 6x^2=4-8x

The zeros of 6x^2=4-8x are x=(-2+sqrt(10))/3 ,x=-(2+sqrt(10))/3

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6 x^{2} = 4 - 8 x

x = \frac{- 2 + 10}{3}, x = - \frac{2 + 10}{3}

Decimal Notation

x = 0.38742 \dots, x = - 1.72075 \dots

Solution steps

6 x^{2} = 4 - 8 x

Move

8 x

to the left side

6 x^{2} + 8 x = 4

Move

4

to the left side

6 x^{2} + 8 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 6 ( - 4 )}{2 \cdot 6}

8^{2} - 4 \cdot 6 (- 4) = 410

x_{1, 2} = \frac{- 8 \pm 4 10}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 8 + 4 10}{2 \cdot 6}, x_{2} = \frac{- 8 - 4 10}{2 \cdot 6}

x = \frac{- 8 + 4 10}{2 \cdot 6} : \frac{- 2 + 10}{3}

x = \frac{- 8 - 4 10}{2 \cdot 6} : - \frac{2 + 10}{3}

The solutions to the quadratic equation are:

x = \frac{- 2 + 10}{3}, x = - \frac{2 + 10}{3}

x, x^{2} - x = 12

2 ab x^{2} - (b^{2} + 6 a^{2}) x + 3 ab = 0

0 = - 4.9 t^{2} + 100 t + 20

- 1.86 x^{2} + 18.76 x + 1.21 = 10

(2 x - 5)^{2} = 4242

What are the solutions to the equation 6x^2=4-8x ?
The solutions to the equation 6x^2=4-8x are x=(-2+sqrt(10))/3 ,x=-(2+sqrt(10))/3
Find the zeros of 6x^2=4-8x
The zeros of 6x^2=4-8x are x=(-2+sqrt(10))/3 ,x=-(2+sqrt(10))/3