What are the solutions to the equation (2x-5)^2=4242 ?

The solutions to the equation (2x-5)^2=4242 are x=(sqrt(4242)+5)/2 ,x=(-sqrt(4242)+5)/2

Find the zeros of (2x-5)^2=4242

The zeros of (2x-5)^2=4242 are x=(sqrt(4242)+5)/2 ,x=(-sqrt(4242)+5)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2 x - 5)^{2} = 4242

x = \frac{4242 + 5}{2}, x = \frac{- 4242 + 5}{2}

Decimal Notation

x = 35.06531 \dots, x = - 30.06531 \dots

Solution steps

(2 x - 5)^{2} = 4242

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 5 = 4242 : x = \frac{4242 + 5}{2}

Solve

2 x - 5 = - 4242 : x = \frac{- 4242 + 5}{2}

The solutions to the quadratic equation are:

x = \frac{4242 + 5}{2}, x = \frac{- 4242 + 5}{2}

3 m (m - 1) - 9 = 2 m (m - 3) + 4

4 w^{2} + 12 w = - 9

- 0.2 x^{2} + 3 x + 0.25 = 0

- 110 = 10 - 5 x^{2}

x^{2} + 13 x + 27 = 0

What are the solutions to the equation (2x-5)^2=4242 ?
The solutions to the equation (2x-5)^2=4242 are x=(sqrt(4242)+5)/2 ,x=(-sqrt(4242)+5)/2
Find the zeros of (2x-5)^2=4242
The zeros of (2x-5)^2=4242 are x=(sqrt(4242)+5)/2 ,x=(-sqrt(4242)+5)/2