What are the solutions to the equation -2^2+3^2=c^2 ?

The solutions to the equation -2^2+3^2=c^2 are c=sqrt(5),c=-sqrt(5)

Find the zeros of -2^2+3^2=c^2

The zeros of -2^2+3^2=c^2 are c=sqrt(5),c=-sqrt(5)

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- 2^{2} + 3^{2} = c^{2}

c = 5, c = - 5

Decimal Notation

c = 2.23606 \dots, c = - 2.23606 \dots

Solution steps

- 2^{2} + 3^{2} = c^{2}

Switch sides

c^{2} = - 2^{2} + 3^{2}

Simplify

- 2^{2} + 3^{2} : 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 5, c = - 5

4 x^{2} + 4 x + 65

y, 4 y^{2} + 18 = 96 x

2 q^{2} + 9 = - q

(x + 3) (x + 7) = 11

2 c^{2} - 3 c - 9 = 0

What are the solutions to the equation -2^2+3^2=c^2 ?
The solutions to the equation -2^2+3^2=c^2 are c=sqrt(5),c=-sqrt(5)
Find the zeros of -2^2+3^2=c^2
The zeros of -2^2+3^2=c^2 are c=sqrt(5),c=-sqrt(5)