What are the solutions to the equation (x+3)(x+7)=11 ?

The solutions to the equation (x+3)(x+7)=11 are x=-5+sqrt(15),x=-5-sqrt(15)

Find the zeros of (x+3)(x+7)=11

The zeros of (x+3)(x+7)=11 are x=-5+sqrt(15),x=-5-sqrt(15)

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(x + 3) (x + 7) = 11

x = - 5 + 15, x = - 5 - 15

Decimal Notation

x = - 1.12701 \dots, x = - 8.87298 \dots

Solution steps

(x + 3) (x + 7) = 11

Expand

(x + 3) (x + 7) : x^{2} + 10 x + 21

x^{2} + 10 x + 21 = 11

Move

11

to the left side

x^{2} + 10 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 10 = 215

x_{1, 2} = \frac{- 10 \pm 2 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 15}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 15}{2 \cdot 1}

x = \frac{- 10 + 2 15}{2 \cdot 1} : - 5 + 15

x = \frac{- 10 - 2 15}{2 \cdot 1} : - 5 - 15

The solutions to the quadratic equation are:

x = - 5 + 15, x = - 5 - 15

2 c^{2} - 3 c - 9 = 0

(3 x + 5)^{2} - \frac{1}{3} = 0

X^{2} - 4 X + 1 = 0

2 x^{2} + 12 x - 10 = 0

x, g = p (x - q)^{2} + r - 3

What are the solutions to the equation (x+3)(x+7)=11 ?
The solutions to the equation (x+3)(x+7)=11 are x=-5+sqrt(15),x=-5-sqrt(15)
Find the zeros of (x+3)(x+7)=11
The zeros of (x+3)(x+7)=11 are x=-5+sqrt(15),x=-5-sqrt(15)