What are the solutions to the equation (3x+5)^2-1/3 =0 ?

The solutions to the equation (3x+5)^2-1/3 =0 are x=(sqrt(1/3)-5)/3 ,x=(-sqrt(1/3)-5)/3

Find the zeros of (3x+5)^2-1/3 =0

The zeros of (3x+5)^2-1/3 =0 are x=(sqrt(1/3)-5)/3 ,x=(-sqrt(1/3)-5)/3

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(3 x + 5)^{2} - \frac{1}{3} = 0

x = \frac{\frac{1}{3} - 5}{3}, x = \frac{- \frac{1}{3} - 5}{3}

Decimal Notation

x = - 1.47421 \dots, x = - 1.85911 \dots

Solution steps

(3 x + 5)^{2} - \frac{1}{3} = 0

Move

\frac{1}{3}

to the right side

(3 x + 5)^{2} = \frac{1}{3}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 5 = \frac{1}{3} : x = \frac{\frac{1}{3} - 5}{3}

Solve

3 x + 5 = - \frac{1}{3} : x = \frac{- \frac{1}{3} - 5}{3}

The solutions to the quadratic equation are:

x = \frac{\frac{1}{3} - 5}{3}, x = \frac{- \frac{1}{3} - 5}{3}

X^{2} - 4 X + 1 = 0

2 x^{2} + 12 x - 10 = 0

x, g = p (x - q)^{2} + r - 3

x^{2} - 242 = 0

- 6 x^{2} + 36 x - 84 = 0

What are the solutions to the equation (3x+5)^2-1/3 =0 ?
The solutions to the equation (3x+5)^2-1/3 =0 are x=(sqrt(1/3)-5)/3 ,x=(-sqrt(1/3)-5)/3
Find the zeros of (3x+5)^2-1/3 =0
The zeros of (3x+5)^2-1/3 =0 are x=(sqrt(1/3)-5)/3 ,x=(-sqrt(1/3)-5)/3