What are the solutions to the equation 3x^2=1200 ?

The solutions to the equation 3x^2=1200 are x=20,x=-20

Find the zeros of 3x^2=1200

The zeros of 3x^2=1200 are x=20,x=-20

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3 x^{2} = 1200

x = 20, x = - 20

Solution steps

3 x^{2} = 1200

Divide both sides by

3

x^{2} = 400

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 400, x = - 400

400 = 20

- 400 = - 20

x = 20, x = - 20

1 - 3 x + 2 x^{2} = 0

3 x^{2} + 2 x - 2 - 3 = 0

- 2 y^{2} - 5 y + 6 = 0

3 s^{2} + 0.5 s + 2 = 0

- x^{2} + 0 x + 1 = 0

What are the solutions to the equation 3x^2=1200 ?
The solutions to the equation 3x^2=1200 are x=20,x=-20
Find the zeros of 3x^2=1200
The zeros of 3x^2=1200 are x=20,x=-20