What are the solutions to the equation (x+7)(x-7)=-7 ?

The solutions to the equation (x+7)(x-7)=-7 are x=sqrt(42),x=-sqrt(42)

Find the zeros of (x+7)(x-7)=-7

The zeros of (x+7)(x-7)=-7 are x=sqrt(42),x=-sqrt(42)

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(x + 7) (x - 7) = - 7

x = 42, x = - 42

Decimal Notation

x = 6.48074 \dots, x = - 6.48074 \dots

Solution steps

(x + 7) (x - 7) = - 7

Expand

(x + 7) (x - 7) : x^{2} - 49

x^{2} - 49 = - 7

Move

7

to the left side

x^{2} - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 42 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 42) = 242

x_{1, 2} = \frac{- 0 \pm 2 42}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 2 42}{2 \cdot 1}, x_{2} = \frac{- 0 - 2 42}{2 \cdot 1}

x = \frac{- 0 + 2 42}{2 \cdot 1} : 42

x = \frac{- 0 - 2 42}{2 \cdot 1} : - 42

The solutions to the quadratic equation are:

x = 42, x = - 42

y^{2} - 4 y = 12

30.7886 X^{2} + 68.4915 X - 60 = 0

x (x - 12) = 38

w^{2} = 3 (w - 2)

x^{2} - 2 = 47

What are the solutions to the equation (x+7)(x-7)=-7 ?
The solutions to the equation (x+7)(x-7)=-7 are x=sqrt(42),x=-sqrt(42)
Find the zeros of (x+7)(x-7)=-7
The zeros of (x+7)(x-7)=-7 are x=sqrt(42),x=-sqrt(42)