What are the solutions to the equation x(x-12)=38 ?

The solutions to the equation x(x-12)=38 are x=6+sqrt(74),x=6-sqrt(74)

Find the zeros of x(x-12)=38

The zeros of x(x-12)=38 are x=6+sqrt(74),x=6-sqrt(74)

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x (x - 12) = 38

x = 6 + 74, x = 6 - 74

Decimal Notation

x = 14.60232 \dots, x = - 2.60232 \dots

Solution steps

x (x - 12) = 38

Expand

x (x - 12) : x^{2} - 12 x

x^{2} - 12 x = 38

Move

38

to the left side

x^{2} - 12 x - 38 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 38 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 38) = 274

x_{1, 2} = \frac{- ( - 12 ) \pm 2 74}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 74}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 74}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 74}{2 \cdot 1} : 6 + 74

x = \frac{- ( - 12 ) - 2 74}{2 \cdot 1} : 6 - 74

The solutions to the quadratic equation are:

x = 6 + 74, x = 6 - 74

w^{2} = 3 (w - 2)

x^{2} - 2 = 47

x^{2} = 3^{2}

(5 x + 1)^{2} = 9

x^{2} + \frac{5}{4} = x

What are the solutions to the equation x(x-12)=38 ?
The solutions to the equation x(x-12)=38 are x=6+sqrt(74),x=6-sqrt(74)
Find the zeros of x(x-12)=38
The zeros of x(x-12)=38 are x=6+sqrt(74),x=6-sqrt(74)