What are the solutions to the equation (5x+1)^2=9 ?

The solutions to the equation (5x+1)^2=9 are x= 2/5 ,x=-4/5

Find the zeros of (5x+1)^2=9

The zeros of (5x+1)^2=9 are x= 2/5 ,x=-4/5

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(5 x + 1)^{2} = 9

x = \frac{2}{5}, x = - \frac{4}{5}

Decimal Notation

x = 0.4, x = - 0.8

Solution steps

(5 x + 1)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 1 = 9 : x = \frac{2}{5}

Solve

5 x + 1 = - 9 : x = - \frac{4}{5}

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = - \frac{4}{5}

x^{2} + \frac{5}{4} = x

x^{2} + 1 x - (1 + 7) = 0

2 x - 1 = x (x) - 1

(1 - y)^{2} = 0

96 = 96 + 80 t - 16 t^{2}

What are the solutions to the equation (5x+1)^2=9 ?
The solutions to the equation (5x+1)^2=9 are x= 2/5 ,x=-4/5
Find the zeros of (5x+1)^2=9
The zeros of (5x+1)^2=9 are x= 2/5 ,x=-4/5