What are the solutions to the equation (1-y)^2=0 ?

The solutions to the equation (1-y)^2=0 are y=1

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(1-y)^2=0

(1 - y)^{2} = 0

y = 1

Solution steps

(1 - y)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

1 - y = 0 : y = 1

The solution to the quadratic equation is:

y = 1

96 = 96 + 80 t - 16 t^{2}

6 - x^{2} = 2

4 x^{2} + 20 = - 13

(8 - R)^{2} + (4 - R)^{2} = R^{2}

(x) = 4 x^{2} - 3

What are the solutions to the equation (1-y)^2=0 ?
The solutions to the equation (1-y)^2=0 are y=1
Find the zeros of (1-y)^2=0
The zeros of (1-y)^2=0 are y=1