What are the solutions to the equation 4p(p-2)=4-2p ?

The solutions to the equation 4p(p-2)=4-2p are p=2,p=-1/2

Find the zeros of 4p(p-2)=4-2p

The zeros of 4p(p-2)=4-2p are p=2,p=-1/2

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4 p (p - 2) = 4 - 2 p

p = 2, p = - \frac{1}{2}

Decimal Notation

p = 2, p = - 0.5

Solution steps

4 p (p - 2) = 4 - 2 p

Expand

4 p (p - 2) : 4 p^{2} - 8 p

4 p^{2} - 8 p = 4 - 2 p

Move

2 p

to the left side

4 p^{2} - 6 p = 4

Move

4

to the left side

4 p^{2} - 6 p - 4 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 4 ( - 4 )}{2 \cdot 4}

(- 6)^{2} - 4 \cdot 4 (- 4) = 10

p_{1, 2} = \frac{- ( - 6 ) \pm 10}{2 \cdot 4}

Separate the solutions

p_{1} = \frac{- ( - 6 ) + 10}{2 \cdot 4}, p_{2} = \frac{- ( - 6 ) - 10}{2 \cdot 4}

p = \frac{- ( - 6 ) + 10}{2 \cdot 4} : 2

p = \frac{- ( - 6 ) - 10}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

p = 2, p = - \frac{1}{2}

x, x^{2} - 2 x - 48 = 0

x^{2} - 10 = 24

8 x^{2} - 12 x + 1 = 0

x^{2} - 10 = 2 x

x^{2} = 6 (x + 1)

What are the solutions to the equation 4p(p-2)=4-2p ?
The solutions to the equation 4p(p-2)=4-2p are p=2,p=-1/2
Find the zeros of 4p(p-2)=4-2p
The zeros of 4p(p-2)=4-2p are p=2,p=-1/2