What are the solutions to the equation x^2-10=2x ?

The solutions to the equation x^2-10=2x are x=1+sqrt(11),x=1-sqrt(11)

Find the zeros of x^2-10=2x

The zeros of x^2-10=2x are x=1+sqrt(11),x=1-sqrt(11)

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x^{2} - 10 = 2 x

x = 1 + 11, x = 1 - 11

Decimal Notation

x = 4.31662 \dots, x = - 2.31662 \dots

Solution steps

x^{2} - 10 = 2 x

Move

2 x

to the left side

x^{2} - 10 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 10) = 211

x_{1, 2} = \frac{- ( - 2 ) \pm 2 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 11}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 11}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 11}{2 \cdot 1} : 1 + 11

x = \frac{- ( - 2 ) - 2 11}{2 \cdot 1} : 1 - 11

The solutions to the quadratic equation are:

x = 1 + 11, x = 1 - 11

x^{2} = 6 (x + 1)

32 n^{2} - 162 = 0

x^{2} - 5 x + 4 = 0

- 18 x^{2} - 70 x + 8 = 0

2 x^{2} + 5 = 7 x

What are the solutions to the equation x^2-10=2x ?
The solutions to the equation x^2-10=2x are x=1+sqrt(11),x=1-sqrt(11)
Find the zeros of x^2-10=2x
The zeros of x^2-10=2x are x=1+sqrt(11),x=1-sqrt(11)