What are the solutions to the equation (3x+6)(2x-10)=0 ?

The solutions to the equation (3x+6)(2x-10)=0 are x=-2,x=5

Find the zeros of (3x+6)(2x-10)=0

The zeros of (3x+6)(2x-10)=0 are x=-2,x=5

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(3 x + 6) (2 x - 10) = 0

x = - 2, x = 5

Solution steps

(3 x + 6) (2 x - 10) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 6 = 0 or 2 x - 10 = 0

Solve

3 x + 6 = 0 : x = - 2

Solve

2 x - 10 = 0 : x = 5

The solutions to the quadratic equation are:

x = - 2, x = 5

4 a^{3} b^{2} 0.3 a^{- 4} b^{- 3}

64 t^{6} - 9 k^{8}

(9 \cdot \frac{5}{6})^{2}

3 x^{2} + 7 = 0

3 (8)^{\frac{1}{3}}

What are the solutions to the equation (3x+6)(2x-10)=0 ?
The solutions to the equation (3x+6)(2x-10)=0 are x=-2,x=5
Find the zeros of (3x+6)(2x-10)=0
The zeros of (3x+6)(2x-10)=0 are x=-2,x=5