What are the solutions to the equation 1-0.8x-0.16x^2=0 ?

The solutions to the equation 1-0.8x-0.16x^2=0 are x=-(5(1+sqrt(2)))/2 ,x=(5(sqrt(2)-1))/2

Find the zeros of 1-0.8x-0.16x^2=0

The zeros of 1-0.8x-0.16x^2=0 are x=-(5(1+sqrt(2)))/2 ,x=(5(sqrt(2)-1))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1 - 0.8 x - 0.16 x^{2} = 0

x = - \frac{5 ( 1 + 2 )}{2}, x = \frac{5 ( 2 - 1 )}{2}

Decimal Notation

x = - 6.03553 \dots, x = 1.03553 \dots

Solution steps

1 - 0.8 x - 0.16 x^{2} = 0

Multiply both sides by

100

100 - 80 x - 16 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 x^{2} - 80 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 80 ) \pm ( - 80 ) ^{2} - 4 ( - 16 ) \cdot 100}{2 ( - 16 )}

(- 80)^{2} - 4 (- 16) \cdot 100 = 802

x_{1, 2} = \frac{- ( - 80 ) \pm 80 2}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- ( - 80 ) + 80 2}{2 ( - 16 )}, x_{2} = \frac{- ( - 80 ) - 80 2}{2 ( - 16 )}

x = \frac{- ( - 80 ) + 80 2}{2 ( - 16 )} : - \frac{5 ( 1 + 2 )}{2}

x = \frac{- ( - 80 ) - 80 2}{2 ( - 16 )} : \frac{5 ( 2 - 1 )}{2}

The solutions to the quadratic equation are:

x = - \frac{5 ( 1 + 2 )}{2}, x = \frac{5 ( 2 - 1 )}{2}

12 x^{2} + 8 x = 20

a^{2} + 4 0^{2} = 4 1^{2}

1 4^{2} + 2 0^{2} = c^{2}

x^{2} + 12 x + 400 = 0

x^{2} + 5 x + 1 = 8

What are the solutions to the equation 1-0.8x-0.16x^2=0 ?
The solutions to the equation 1-0.8x-0.16x^2=0 are x=-(5(1+sqrt(2)))/2 ,x=(5(sqrt(2)-1))/2
Find the zeros of 1-0.8x-0.16x^2=0
The zeros of 1-0.8x-0.16x^2=0 are x=-(5(1+sqrt(2)))/2 ,x=(5(sqrt(2)-1))/2