What are the solutions to the equation x^2+12x+400=0 ?

The solutions to the equation x^2+12x+400=0 are x=-6+2sqrt(91)i,x=-6-2sqrt(91)i

Find the zeros of x^2+12x+400=0

The zeros of x^2+12x+400=0 are x=-6+2sqrt(91)i,x=-6-2sqrt(91)i

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x^{2} + 12 x + 400 = 0

x = - 6 + 291 i, x = - 6 - 291 i

Solution steps

x^{2} + 12 x + 400 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 400}{2 \cdot 1}

Simplify

1 2^{2} - 4 \cdot 1 \cdot 400 : 491 i

x_{1, 2} = \frac{- 12 \pm 4 91 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 4 91 i}{2 \cdot 1}, x_{2} = \frac{- 12 - 4 91 i}{2 \cdot 1}

x = \frac{- 12 + 4 91 i}{2 \cdot 1} : - 6 + 291 i

x = \frac{- 12 - 4 91 i}{2 \cdot 1} : - 6 - 291 i

The solutions to the quadratic equation are:

x = - 6 + 291 i, x = - 6 - 291 i

x^{2} + 5 x + 1 = 8

6 p^{2} - 5 = 2 + 5 p^{2} - 6 p

0 = 3 t^{2} - 12 t - 15

4 x^{2} + 180 = 0

2 x^{2} + 9 + 10 = 0

What are the solutions to the equation x^2+12x+400=0 ?
The solutions to the equation x^2+12x+400=0 are x=-6+2sqrt(91)i,x=-6-2sqrt(91)i
Find the zeros of x^2+12x+400=0
The zeros of x^2+12x+400=0 are x=-6+2sqrt(91)i,x=-6-2sqrt(91)i