What are the solutions to the equation (p-3)^2-4(p-3)^2+3=0 ?

The solutions to the equation (p-3)^2-4(p-3)^2+3=0 are p=4,p=2

Find the zeros of (p-3)^2-4(p-3)^2+3=0

The zeros of (p-3)^2-4(p-3)^2+3=0 are p=4,p=2

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(p - 3)^{2} - 4 (p - 3)^{2} + 3 = 0

p = 4, p = 2

Solution steps

(p - 3)^{2} - 4 (p - 3)^{2} + 3 = 0

Move

3

to the right side

(p - 3)^{2} - 4 (p - 3)^{2} = - 3

Add similar elements:

(p - 3)^{2} - 4 (p - 3)^{2} = - 3 (p - 3)^{2}

- 3 (p - 3)^{2} = - 3

Divide both sides by

- 3

(p - 3)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

p - 3 = 1 : p = 4

Solve

p - 3 = - 1 : p = 2

The solutions to the quadratic equation are:

p = 4, p = 2

4 x + x^{2} = 21

x^{2} + 3 x - 1 = 0

12 x^{2} + 25 x + 7 = 0

x^{2} - 1 - x - 22 = 0

2 x^{2} + 8 x - 15 = 0

What are the solutions to the equation (p-3)^2-4(p-3)^2+3=0 ?
The solutions to the equation (p-3)^2-4(p-3)^2+3=0 are p=4,p=2
Find the zeros of (p-3)^2-4(p-3)^2+3=0
The zeros of (p-3)^2-4(p-3)^2+3=0 are p=4,p=2