What are the solutions to the equation x^2-1-x-22=0 ?

The solutions to the equation x^2-1-x-22=0 are x=(1+sqrt(93))/2 ,x=(1-sqrt(93))/2

Find the zeros of x^2-1-x-22=0

The zeros of x^2-1-x-22=0 are x=(1+sqrt(93))/2 ,x=(1-sqrt(93))/2

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x^{2} - 1 - x - 22 = 0

x = \frac{1 + 93}{2}, x = \frac{1 - 93}{2}

Decimal Notation

x = 5.32182 \dots, x = - 4.32182 \dots

Solution steps

x^{2} - 1 - x - 22 = 0

Refine

x^{2} - x - 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 23 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 23) = 93

x_{1, 2} = \frac{- ( - 1 ) \pm 93}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 93}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 93}{2 \cdot 1}

x = \frac{- ( - 1 ) + 93}{2 \cdot 1} : \frac{1 + 93}{2}

x = \frac{- ( - 1 ) - 93}{2 \cdot 1} : \frac{1 - 93}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 93}{2}, x = \frac{1 - 93}{2}

2 x^{2} + 8 x - 15 = 0

x^{2} - 12 x - 49 = 0

4 x^{2} - 24 x - 64 = 0

0 = 0 + 43.3 \cdot t - 5 t^{2}

36 x^{2} - 84 x + 49 = 0

What are the solutions to the equation x^2-1-x-22=0 ?
The solutions to the equation x^2-1-x-22=0 are x=(1+sqrt(93))/2 ,x=(1-sqrt(93))/2
Find the zeros of x^2-1-x-22=0
The zeros of x^2-1-x-22=0 are x=(1+sqrt(93))/2 ,x=(1-sqrt(93))/2