What are the solutions to the equation 0=0+43.3*t-5t^2 ?

The solutions to the equation 0=0+43.3*t-5t^2 are t=0,t= 433/50

Find the zeros of 0=0+43.3*t-5t^2

The zeros of 0=0+43.3*t-5t^2 are t=0,t= 433/50

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0 = 0 + 43.3 \cdot t - 5 t^{2}

t = 0, t = \frac{433}{50}

Decimal Notation

t = 0, t = 8.66

Solution steps

0 = 0 + 43.3 t - 5 t^{2}

Multiply both sides by

10

0 = - 50 t^{2} + 433 t

Switch sides

- 50 t^{2} + 433 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 433 \pm 43 3 ^{2} - 4 ( - 50 ) \cdot 0}{2 ( - 50 )}

43 3^{2} - 4 (- 50) \cdot 0 = 433

t_{1, 2} = \frac{- 433 \pm 433}{2 ( - 50 )}

Separate the solutions

t_{1} = \frac{- 433 + 433}{2 ( - 50 )}, t_{2} = \frac{- 433 - 433}{2 ( - 50 )}

t = \frac{- 433 + 433}{2 ( - 50 )} : 0

t = \frac{- 433 - 433}{2 ( - 50 )} : \frac{433}{50}

The solutions to the quadratic equation are:

t = 0, t = \frac{433}{50}

36 x^{2} - 84 x + 49 = 0

x^{2} = 62

x, y^{2} = x^{2} + 2 a d

5 a^{2} - 20 = 0

16 x^{2} - x = 0

What are the solutions to the equation 0=0+43.3*t-5t^2 ?
The solutions to the equation 0=0+43.3*t-5t^2 are t=0,t= 433/50
Find the zeros of 0=0+43.3*t-5t^2
The zeros of 0=0+43.3*t-5t^2 are t=0,t= 433/50