What are the solutions to the equation completesquare 16x^2-x=0 ?

The solutions to the equation completesquare 16x^2-x=0 are x= 1/16 ,x=0

Find the zeros of completesquare 16x^2-x=0

The zeros of completesquare 16x^2-x=0 are x= 1/16 ,x=0

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16 x^{2} - x = 0

x = \frac{1}{16}, x = 0

Decimal Notation

x = 0.0625, x = 0

Solution steps

16 x^{2} - x = 0

Divide both sides by

16

\frac{16 x ^{2} - x}{16} = \frac{0}{16}

x^{2} - \frac{x}{16} = 0

Rewrite in the form

(x + a)^{2} = b

(x - \frac{1}{32})^{2} = \frac{1}{1024}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{1}{32} = \frac{1}{1024} : x = \frac{1}{16}

Solve

x - \frac{1}{32} = - \frac{1}{1024} : x = 0

The solutions to the quadratic equation are:

x = \frac{1}{16}, x = 0

2 m^{2} - 7 m + 3 = 0

6 x (x - 1) = 15 - 5 x

4 = 2 x^{2} - 4

(2 y + 20)^{2} = 27

- x^{2} + 6 x + 1

What are the solutions to the equation completesquare 16x^2-x=0 ?
The solutions to the equation completesquare 16x^2-x=0 are x= 1/16 ,x=0
Find the zeros of completesquare 16x^2-x=0
The zeros of completesquare 16x^2-x=0 are x= 1/16 ,x=0