What are the solutions to the equation 6x(x-1)=15-5x ?

The solutions to the equation 6x(x-1)=15-5x are x= 5/3 ,x=-3/2

Find the zeros of 6x(x-1)=15-5x

The zeros of 6x(x-1)=15-5x are x= 5/3 ,x=-3/2

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6 x (x - 1) = 15 - 5 x

x = \frac{5}{3}, x = - \frac{3}{2}

Decimal Notation

x = 1.66666 \dots, x = - 1.5

Solution steps

6 x (x - 1) = 15 - 5 x

Expand

6 x (x - 1) : 6 x^{2} - 6 x

6 x^{2} - 6 x = 15 - 5 x

Move

5 x

to the left side

6 x^{2} - x = 15

Move

15

to the left side

6 x^{2} - x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 6 ( - 15 )}{2 \cdot 6}

(- 1)^{2} - 4 \cdot 6 (- 15) = 19

x_{1, 2} = \frac{- ( - 1 ) \pm 19}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 19}{2 \cdot 6}, x_{2} = \frac{- ( - 1 ) - 19}{2 \cdot 6}

x = \frac{- ( - 1 ) + 19}{2 \cdot 6} : \frac{5}{3}

x = \frac{- ( - 1 ) - 19}{2 \cdot 6} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = - \frac{3}{2}

4 = 2 x^{2} - 4

(2 y + 20)^{2} = 27

- x^{2} + 6 x + 1

x^{2} - 144 x = 0

3 x^{2} + 12 x + 28 = 0

What are the solutions to the equation 6x(x-1)=15-5x ?
The solutions to the equation 6x(x-1)=15-5x are x= 5/3 ,x=-3/2
Find the zeros of 6x(x-1)=15-5x
The zeros of 6x(x-1)=15-5x are x= 5/3 ,x=-3/2