What are the solutions to the equation 5(2n-1)^2=45 ?

The solutions to the equation 5(2n-1)^2=45 are n=2,n=-1

Find the zeros of 5(2n-1)^2=45

The zeros of 5(2n-1)^2=45 are n=2,n=-1

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5 (2 n - 1)^{2} = 45

n = 2, n = - 1

Solution steps

5 (2 n - 1)^{2} = 45

Divide both sides by

5

(2 n - 1)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 n - 1 = 9 : n = 2

Solve

2 n - 1 = - 9 : n = - 1

The solutions to the quadratic equation are:

n = 2, n = - 1

2 x^{2} + 4 x = 8

5 x^{2} + 8 x - 8 = 0

(3 - h)^{2} + (5 - k)^{2} = r^{2}

5 a^{2} + 21 = 49

(2 x - 3)^{2} - 9 = 0

What are the solutions to the equation 5(2n-1)^2=45 ?
The solutions to the equation 5(2n-1)^2=45 are n=2,n=-1
Find the zeros of 5(2n-1)^2=45
The zeros of 5(2n-1)^2=45 are n=2,n=-1