What are the solutions to the equation 5a^2+21=49 ?

The solutions to the equation 5a^2+21=49 are a=(2sqrt(7))/(sqrt(5)),a=-(2sqrt(7))/(sqrt(5))

Find the zeros of 5a^2+21=49

The zeros of 5a^2+21=49 are a=(2sqrt(7))/(sqrt(5)),a=-(2sqrt(7))/(sqrt(5))

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5 a^{2} + 21 = 49

a = \frac{2 7}{5}, a = - \frac{2 7}{5}

Decimal Notation

a = 2.36643 \dots, a = - 2.36643 \dots

Solution steps

5 a^{2} + 21 = 49

Move

21

to the right side

5 a^{2} = 28

Divide both sides by

5

a^{2} = \frac{28}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = \frac{28}{5}, a = - \frac{28}{5}

\frac{28}{5} = \frac{2 7}{5}

- \frac{28}{5} = - \frac{2 7}{5}

a = \frac{2 7}{5}, a = - \frac{2 7}{5}

(2 x - 3)^{2} - 9 = 0

x - 1 = x^{2} - 4 x + 3

0 = - x^{2} + 10 x - 8

55 - 24 b + 2 b^{2} = 1

x^{2} + 6 x - 10 = 0

What are the solutions to the equation 5a^2+21=49 ?
The solutions to the equation 5a^2+21=49 are a=(2sqrt(7))/(sqrt(5)),a=-(2sqrt(7))/(sqrt(5))
Find the zeros of 5a^2+21=49
The zeros of 5a^2+21=49 are a=(2sqrt(7))/(sqrt(5)),a=-(2sqrt(7))/(sqrt(5))