What are the solutions to the equation 55-24b+2b^2=1 ?

The solutions to the equation 55-24b+2b^2=1 are b=9,b=3

Find the zeros of 55-24b+2b^2=1

The zeros of 55-24b+2b^2=1 are b=9,b=3

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55 - 24 b + 2 b^{2} = 1

b = 9, b = 3

Solution steps

55 - 24 b + 2 b^{2} = 1

Move

1

to the left side

2 b^{2} - 24 b + 54 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 2 \cdot 54}{2 \cdot 2}

(- 24)^{2} - 4 \cdot 2 \cdot 54 = 12

b_{1, 2} = \frac{- ( - 24 ) \pm 12}{2 \cdot 2}

Separate the solutions

b_{1} = \frac{- ( - 24 ) + 12}{2 \cdot 2}, b_{2} = \frac{- ( - 24 ) - 12}{2 \cdot 2}

b = \frac{- ( - 24 ) + 12}{2 \cdot 2} : 9

b = \frac{- ( - 24 ) - 12}{2 \cdot 2} : 3

The solutions to the quadratic equation are:

b = 9, b = 3

x^{2} + 6 x - 10 = 0

15 x^{2} + 6 x = 0

10 = \frac{t ^{2} - t}{2}

4 x^{2} - 49 x = 12

x^{2} - 5 x + 8 = 0

What are the solutions to the equation 55-24b+2b^2=1 ?
The solutions to the equation 55-24b+2b^2=1 are b=9,b=3
Find the zeros of 55-24b+2b^2=1
The zeros of 55-24b+2b^2=1 are b=9,b=3