What are the solutions to the equation (2x-3)^2-5=5 ?

The solutions to the equation (2x-3)^2-5=5 are x=(sqrt(10)+3)/2 ,x=(-sqrt(10)+3)/2

Find the zeros of (2x-3)^2-5=5

The zeros of (2x-3)^2-5=5 are x=(sqrt(10)+3)/2 ,x=(-sqrt(10)+3)/2

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(2 x - 3)^{2} - 5 = 5

x = \frac{10 + 3}{2}, x = \frac{- 10 + 3}{2}

Decimal Notation

x = 3.08113 \dots, x = - 0.08113 \dots

Solution steps

(2 x - 3)^{2} - 5 = 5

Move

5

to the right side

(2 x - 3)^{2} = 10

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 3 = 10 : x = \frac{10 + 3}{2}

Solve

2 x - 3 = - 10 : x = \frac{- 10 + 3}{2}

The solutions to the quadratic equation are:

x = \frac{10 + 3}{2}, x = \frac{- 10 + 3}{2}

(2 x - 3)^{2} - 5 = 4

4 x^{2} + 13 x = - 3

2 n^{2} - 8 n = 3

50 = 20 (t) + 0.5 (9.8) \cdot t^{2}

x^{2} + 11 x + 24

What are the solutions to the equation (2x-3)^2-5=5 ?
The solutions to the equation (2x-3)^2-5=5 are x=(sqrt(10)+3)/2 ,x=(-sqrt(10)+3)/2
Find the zeros of (2x-3)^2-5=5
The zeros of (2x-3)^2-5=5 are x=(sqrt(10)+3)/2 ,x=(-sqrt(10)+3)/2