What are the solutions to the equation 2n^2-8n=3 ?

The solutions to the equation 2n^2-8n=3 are n=(4+sqrt(22))/2 ,n=(4-sqrt(22))/2

Find the zeros of 2n^2-8n=3

The zeros of 2n^2-8n=3 are n=(4+sqrt(22))/2 ,n=(4-sqrt(22))/2

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2 n^{2} - 8 n = 3

n = \frac{4 + 22}{2}, n = \frac{4 - 22}{2}

Decimal Notation

n = 4.34520 \dots, n = - 0.34520 \dots

Solution steps

2 n^{2} - 8 n = 3

Move

3

to the left side

2 n^{2} - 8 n - 3 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 (- 3) = 222

n_{1, 2} = \frac{- ( - 8 ) \pm 2 22}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- ( - 8 ) + 2 22}{2 \cdot 2}, n_{2} = \frac{- ( - 8 ) - 2 22}{2 \cdot 2}

n = \frac{- ( - 8 ) + 2 22}{2 \cdot 2} : \frac{4 + 22}{2}

n = \frac{- ( - 8 ) - 2 22}{2 \cdot 2} : \frac{4 - 22}{2}

The solutions to the quadratic equation are:

n = \frac{4 + 22}{2}, n = \frac{4 - 22}{2}

50 = 20 (t) + 0.5 (9.8) \cdot t^{2}

x^{2} + 11 x + 24

7^{2} + 2^{2} = x^{2}

(x + 9)^{2} + 64 = 0

3 x^{2} + 7 x + 3 = x^{2} + 2 x

What are the solutions to the equation 2n^2-8n=3 ?
The solutions to the equation 2n^2-8n=3 are n=(4+sqrt(22))/2 ,n=(4-sqrt(22))/2
Find the zeros of 2n^2-8n=3
The zeros of 2n^2-8n=3 are n=(4+sqrt(22))/2 ,n=(4-sqrt(22))/2