What are the solutions to the equation 7^2+2^2=x^2 ?

The solutions to the equation 7^2+2^2=x^2 are x=sqrt(53),x=-sqrt(53)

Find the zeros of 7^2+2^2=x^2

The zeros of 7^2+2^2=x^2 are x=sqrt(53),x=-sqrt(53)

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7^{2} + 2^{2} = x^{2}

x = 53, x = - 53

Decimal Notation

x = 7.28010 \dots, x = - 7.28010 \dots

Solution steps

7^{2} + 2^{2} = x^{2}

Switch sides

x^{2} = 7^{2} + 2^{2}

Simplify

7^{2} + 2^{2} : 53

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 53, x = - 53

(x + 9)^{2} + 64 = 0

3 x^{2} + 7 x + 3 = x^{2} + 2 x

7 + 5 x - 2 x^{2} = 0

11 a^{2} = - 4 a + 8

x^{2} + 110 = 18 x + 45

What are the solutions to the equation 7^2+2^2=x^2 ?
The solutions to the equation 7^2+2^2=x^2 are x=sqrt(53),x=-sqrt(53)
Find the zeros of 7^2+2^2=x^2
The zeros of 7^2+2^2=x^2 are x=sqrt(53),x=-sqrt(53)