What are the solutions to the equation 11x^2=-10x-11 ?

The solutions to the equation 11x^2=-10x-11 are x=-5/11+i(4sqrt(6))/(11),x=-5/11-i(4sqrt(6))/(11)

Find the zeros of 11x^2=-10x-11

The zeros of 11x^2=-10x-11 are x=-5/11+i(4sqrt(6))/(11),x=-5/11-i(4sqrt(6))/(11)

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11 x^{2} = - 10 x - 11

x = - \frac{5}{11} + i \frac{4 6}{11}, x = - \frac{5}{11} - i \frac{4 6}{11}

Solution steps

11 x^{2} = - 10 x - 11

Move

11

to the left side

11 x^{2} + 11 = - 10 x

Move

10 x

to the left side

11 x^{2} + 11 + 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

11 x^{2} + 10 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 11 \cdot 11}{2 \cdot 11}

Simplify

1 0^{2} - 4 \cdot 11 \cdot 11 : 86 i

x_{1, 2} = \frac{- 10 \pm 8 6 i}{2 \cdot 11}

Separate the solutions

x_{1} = \frac{- 10 + 8 6 i}{2 \cdot 11}, x_{2} = \frac{- 10 - 8 6 i}{2 \cdot 11}

x = \frac{- 10 + 8 6 i}{2 \cdot 11} : - \frac{5}{11} + i \frac{4 6}{11}

x = \frac{- 10 - 8 6 i}{2 \cdot 11} : - \frac{5}{11} - i \frac{4 6}{11}

The solutions to the quadratic equation are:

x = - \frac{5}{11} + i \frac{4 6}{11}, x = - \frac{5}{11} - i \frac{4 6}{11}

m^{2} + 15 m + 50 = 0

9 t^{2} - 15 t - 14 = 0

x^{2} - 4 x - 21

4 x^{2} - 17 x + 1 = 0

x^{2} + 3 x = 0

What are the solutions to the equation 11x^2=-10x-11 ?
The solutions to the equation 11x^2=-10x-11 are x=-5/11+i(4sqrt(6))/(11),x=-5/11-i(4sqrt(6))/(11)
Find the zeros of 11x^2=-10x-11
The zeros of 11x^2=-10x-11 are x=-5/11+i(4sqrt(6))/(11),x=-5/11-i(4sqrt(6))/(11)