What are the solutions to the equation m^2+15m+56=0 ?

The solutions to the equation m^2+15m+56=0 are m=-7,m=-8

Find the zeros of m^2+15m+56=0

The zeros of m^2+15m+56=0 are m=-7,m=-8

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m^{2} + 15 m + 56 = 0

m = - 7, m = - 8

Solution steps

m^{2} + 15 m + 56 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 56 = 1

m_{1, 2} = \frac{- 15 \pm 1}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 15 + 1}{2 \cdot 1}, m_{2} = \frac{- 15 - 1}{2 \cdot 1}

m = \frac{- 15 + 1}{2 \cdot 1} : - 7

m = \frac{- 15 - 1}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

m = - 7, m = - 8

5 (3 - 2 y) 4 y = 3

(x - 5)^{2} + (x - 5) = 0

x, - x^{2} - 3 y^{3} = 5

2 x^{2} = 20 - 3 x^{2}

x, x^{2} + 8 x - 2 = 0

What are the solutions to the equation m^2+15m+56=0 ?
The solutions to the equation m^2+15m+56=0 are m=-7,m=-8
Find the zeros of m^2+15m+56=0
The zeros of m^2+15m+56=0 are m=-7,m=-8