What are the solutions to the equation x^2-20x=-89 ?

The solutions to the equation x^2-20x=-89 are x=10+sqrt(11),x=10-sqrt(11)

Find the zeros of x^2-20x=-89

The zeros of x^2-20x=-89 are x=10+sqrt(11),x=10-sqrt(11)

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x^{2} - 20 x = - 89

x = 10 + 11, x = 10 - 11

Decimal Notation

x = 13.31662 \dots, x = 6.68337 \dots

Solution steps

x^{2} - 20 x = - 89

Move

89

to the left side

x^{2} - 20 x + 89 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 89}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 89 = 211

x_{1, 2} = \frac{- ( - 20 ) \pm 2 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 2 11}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 2 11}{2 \cdot 1}

x = \frac{- ( - 20 ) + 2 11}{2 \cdot 1} : 10 + 11

x = \frac{- ( - 20 ) - 2 11}{2 \cdot 1} : 10 - 11

The solutions to the quadratic equation are:

x = 10 + 11, x = 10 - 11

q^{2} - 8 = 17

x^{1} - x^{2} = 0, 3 x^{1} - 2 x^{2} = - 1

15 x^{2} + 7 x = 2

3 x^{2} + 12 x + 11

0 = - 3 x^{2} + 6

What are the solutions to the equation x^2-20x=-89 ?
The solutions to the equation x^2-20x=-89 are x=10+sqrt(11),x=10-sqrt(11)
Find the zeros of x^2-20x=-89
The zeros of x^2-20x=-89 are x=10+sqrt(11),x=10-sqrt(11)